- Problem 4 with the first hint and the results after the first week
- Problem 4 with two hints and the results after two weeks
- Problem 4 with three hints and the results after three weeks
- Problem 4 with final hints and the results after four weeks

This problem was the most technical one out of all the five problems. While the equilbrium angle could be found relatively easily, the oscillation period required calculation of few integrals, and taking few derivatives which were not too difficult in principle, but required patience and accuracy. Although such calculations can be considered to be the most boring part of physics, it is also an inevitable part of it.

Without doubt, the best solution was made by**Navneel Singhal**. This is because he was able to avoid calculation of the integrals by noticing that these integrals give actually the moment of inertia of the triangle. To see this, let us use coordinate system with the origin at the centre of mass, with horizontal *x*-axis and vertical *y*-axis. As hinted , we can assume the velocity of the centre of mass to be negligibly small when calculating the kinetic energy of the system. Using the first hint, one can easily deduce that *v*_{y} must be a linear function of *y*: *v*_{y}=*ay+b*. Since the centre of mass is almost at rest, averaging *v*_{y} over the entire water mass should give zero (when neglecting quadratically small terms). Average of *y* gives the coordinate of the centre of mass, which is zero; hence, *b*=0 so that *v*_{y}=*ay*. The condition of incompressibility of water can be expressed in terms of derivatives as d*v*_{x}/d*x*+d*v*_{y}/d*y*=0, hence *v*_{x}=*-ax*. So, the double kinetic energy of a water element is 2d*K=a*^{2}(*x*^{2}+*y*^{2})d*m*, hence *K=a*^{2}*I*/2, where *I* is the moment of inertia with respect to the centre of mass.

Navneel’s solution, however, is not overhelmingly better than other solutions. Therefore he gets only half of the bonus points, and the rest is divided between the other four well-documented solutions:**Thomas Bergamaschi**;**Dylan Toh**;**Tóbiás Marozsák**;**Muhammad Farhan Husain**.

**And here are the results.** Number of fully correct solutions: 8.

name | school | country | Pr 2: solved; | score |

Navneel Singhal | ALLEN Kota | India | 2 Apr 12:57 | 3.534 |

Dylan Toh | NUS High School | Singapore | 29 Mar 17:52 | 2.939 |

Tóbiás Marozsák | Óbudai Árpád Gimnázium | Hungary | 1 Apr 17:21 | 2.405 |

Dolteanu Stefan | International Computer Highschool Bucharest | Romania | 20 Apr 18:58 | 1.417 |

Stevan K Swadiryus | BPK Penabur 1 SHS Bandung | Indonesia | 17 May 17:49 | 1.331 |

Thomas Bergamaschi | Colegio Etapa Valinhos-Brazil | Brazil | 12 May 18:21 | 1.327 |

Luciano Rodriges | Christus | Brazil | 15 Apr 13:25 | 1.247 |

Muhammad Farhan Husain | Kharisma Bangsa High School | Indonesia | 1 May 13:22 | 1.168 |